Integrand size = 24, antiderivative size = 178 \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=-\frac {\left (a+\frac {c d^2}{e^2}\right ) \sqrt {f+g x}}{2 (e f-d g) (d+e x)^2}+\frac {\left (3 a e^2 g+c d (8 e f-5 d g)\right ) \sqrt {f+g x}}{4 e^2 (e f-d g)^2 (d+e x)}-\frac {\left (3 a e^2 g^2+c \left (8 e^2 f^2-8 d e f g+3 d^2 g^2\right )\right ) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{4 e^{5/2} (e f-d g)^{5/2}} \]
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Time = 0.19 (sec) , antiderivative size = 182, normalized size of antiderivative = 1.02, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {912, 1171, 393, 214} \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=-\frac {\left (3 a e^2 g^2+c \left (3 d^2 g^2-8 d e f g+8 e^2 f^2\right )\right ) \text {arctanh}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{4 e^{5/2} (e f-d g)^{5/2}}-\frac {\sqrt {f+g x} \left (a e^2+c d^2\right )}{2 e^2 (d+e x)^2 (e f-d g)}+\frac {\sqrt {f+g x} \left (3 a e^2 g+c d (8 e f-5 d g)\right )}{4 e^2 (d+e x) (e f-d g)^2} \]
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Rule 214
Rule 393
Rule 912
Rule 1171
Rubi steps \begin{align*} \text {integral}& = \frac {2 \text {Subst}\left (\int \frac {\frac {c f^2+a g^2}{g^2}-\frac {2 c f x^2}{g^2}+\frac {c x^4}{g^2}}{\left (\frac {-e f+d g}{g}+\frac {e x^2}{g}\right )^3} \, dx,x,\sqrt {f+g x}\right )}{g} \\ & = -\frac {\left (c d^2+a e^2\right ) \sqrt {f+g x}}{2 e^2 (e f-d g) (d+e x)^2}+\frac {\text {Subst}\left (\int \frac {-3 a+\frac {c d^2}{e^2}-\frac {4 c f^2}{g^2}+\frac {4 c (e f-d g) x^2}{e g^2}}{\left (\frac {-e f+d g}{g}+\frac {e x^2}{g}\right )^2} \, dx,x,\sqrt {f+g x}\right )}{2 (e f-d g)} \\ & = -\frac {\left (c d^2+a e^2\right ) \sqrt {f+g x}}{2 e^2 (e f-d g) (d+e x)^2}+\frac {\left (3 a e^2 g+c d (8 e f-5 d g)\right ) \sqrt {f+g x}}{4 e^2 (e f-d g)^2 (d+e x)}+\frac {\left (3 a e^2 g^2+c \left (8 e^2 f^2-8 d e f g+3 d^2 g^2\right )\right ) \text {Subst}\left (\int \frac {1}{\frac {-e f+d g}{g}+\frac {e x^2}{g}} \, dx,x,\sqrt {f+g x}\right )}{4 e^2 g (e f-d g)^2} \\ & = -\frac {\left (c d^2+a e^2\right ) \sqrt {f+g x}}{2 e^2 (e f-d g) (d+e x)^2}+\frac {\left (3 a e^2 g+c d (8 e f-5 d g)\right ) \sqrt {f+g x}}{4 e^2 (e f-d g)^2 (d+e x)}-\frac {\left (3 a e^2 g^2+c \left (8 e^2 f^2-8 d e f g+3 d^2 g^2\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{4 e^{5/2} (e f-d g)^{5/2}} \\ \end{align*}
Time = 0.64 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.93 \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=\frac {\frac {\sqrt {e} \sqrt {f+g x} \left (a e^2 (-2 e f+5 d g+3 e g x)+c d \left (-3 d^2 g+8 e^2 f x+d e (6 f-5 g x)\right )\right )}{(e f-d g)^2 (d+e x)^2}+\frac {\left (3 a e^2 g^2+c \left (8 e^2 f^2-8 d e f g+3 d^2 g^2\right )\right ) \arctan \left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {-e f+d g}}\right )}{(-e f+d g)^{5/2}}}{4 e^{5/2}} \]
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Time = 0.50 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.93
method | result | size |
pseudoelliptic | \(\frac {\frac {3 \left (\left (a \,g^{2}+\frac {8 c \,f^{2}}{3}\right ) e^{2}-\frac {8 c d e f g}{3}+c \,d^{2} g^{2}\right ) \left (e x +d \right )^{2} \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )}{4}+\frac {5 \left (-\frac {2 a \left (-\frac {3 g x}{2}+f \right ) e^{3}}{5}+d \left (\frac {8 c f x}{5}+a g \right ) e^{2}+\frac {6 c \left (-\frac {5 g x}{6}+f \right ) d^{2} e}{5}-\frac {3 c \,d^{3} g}{5}\right ) \sqrt {\left (d g -e f \right ) e}\, \sqrt {g x +f}}{4}}{\sqrt {\left (d g -e f \right ) e}\, \left (d g -e f \right )^{2} \left (e x +d \right )^{2} e^{2}}\) | \(166\) |
derivativedivides | \(\frac {\frac {g \left (3 a \,e^{2} g -5 c \,d^{2} g +8 c d e f \right ) \left (g x +f \right )^{\frac {3}{2}}}{4 e \left (d^{2} g^{2}-2 d e f g +e^{2} f^{2}\right )}+\frac {\left (5 a \,e^{2} g -3 c \,d^{2} g +8 c d e f \right ) g \sqrt {g x +f}}{4 e^{2} \left (d g -e f \right )}}{\left (e \left (g x +f \right )+d g -e f \right )^{2}}+\frac {\left (3 a \,e^{2} g^{2}+3 c \,d^{2} g^{2}-8 c d e f g +8 c \,e^{2} f^{2}\right ) \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )}{4 \left (d^{2} g^{2}-2 d e f g +e^{2} f^{2}\right ) e^{2} \sqrt {\left (d g -e f \right ) e}}\) | \(220\) |
default | \(\frac {\frac {g \left (3 a \,e^{2} g -5 c \,d^{2} g +8 c d e f \right ) \left (g x +f \right )^{\frac {3}{2}}}{4 e \left (d^{2} g^{2}-2 d e f g +e^{2} f^{2}\right )}+\frac {\left (5 a \,e^{2} g -3 c \,d^{2} g +8 c d e f \right ) g \sqrt {g x +f}}{4 e^{2} \left (d g -e f \right )}}{\left (e \left (g x +f \right )+d g -e f \right )^{2}}+\frac {\left (3 a \,e^{2} g^{2}+3 c \,d^{2} g^{2}-8 c d e f g +8 c \,e^{2} f^{2}\right ) \arctan \left (\frac {e \sqrt {g x +f}}{\sqrt {\left (d g -e f \right ) e}}\right )}{4 \left (d^{2} g^{2}-2 d e f g +e^{2} f^{2}\right ) e^{2} \sqrt {\left (d g -e f \right ) e}}\) | \(220\) |
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Leaf count of result is larger than twice the leaf count of optimal. 441 vs. \(2 (158) = 316\).
Time = 0.30 (sec) , antiderivative size = 896, normalized size of antiderivative = 5.03 \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=\left [\frac {{\left (8 \, c d^{2} e^{2} f^{2} - 8 \, c d^{3} e f g + 3 \, {\left (c d^{4} + a d^{2} e^{2}\right )} g^{2} + {\left (8 \, c e^{4} f^{2} - 8 \, c d e^{3} f g + 3 \, {\left (c d^{2} e^{2} + a e^{4}\right )} g^{2}\right )} x^{2} + 2 \, {\left (8 \, c d e^{3} f^{2} - 8 \, c d^{2} e^{2} f g + 3 \, {\left (c d^{3} e + a d e^{3}\right )} g^{2}\right )} x\right )} \sqrt {e^{2} f - d e g} \log \left (\frac {e g x + 2 \, e f - d g - 2 \, \sqrt {e^{2} f - d e g} \sqrt {g x + f}}{e x + d}\right ) + 2 \, {\left (2 \, {\left (3 \, c d^{2} e^{3} - a e^{5}\right )} f^{2} - {\left (9 \, c d^{3} e^{2} - 7 \, a d e^{4}\right )} f g + {\left (3 \, c d^{4} e - 5 \, a d^{2} e^{3}\right )} g^{2} + {\left (8 \, c d e^{4} f^{2} - {\left (13 \, c d^{2} e^{3} - 3 \, a e^{5}\right )} f g + {\left (5 \, c d^{3} e^{2} - 3 \, a d e^{4}\right )} g^{2}\right )} x\right )} \sqrt {g x + f}}{8 \, {\left (d^{2} e^{6} f^{3} - 3 \, d^{3} e^{5} f^{2} g + 3 \, d^{4} e^{4} f g^{2} - d^{5} e^{3} g^{3} + {\left (e^{8} f^{3} - 3 \, d e^{7} f^{2} g + 3 \, d^{2} e^{6} f g^{2} - d^{3} e^{5} g^{3}\right )} x^{2} + 2 \, {\left (d e^{7} f^{3} - 3 \, d^{2} e^{6} f^{2} g + 3 \, d^{3} e^{5} f g^{2} - d^{4} e^{4} g^{3}\right )} x\right )}}, \frac {{\left (8 \, c d^{2} e^{2} f^{2} - 8 \, c d^{3} e f g + 3 \, {\left (c d^{4} + a d^{2} e^{2}\right )} g^{2} + {\left (8 \, c e^{4} f^{2} - 8 \, c d e^{3} f g + 3 \, {\left (c d^{2} e^{2} + a e^{4}\right )} g^{2}\right )} x^{2} + 2 \, {\left (8 \, c d e^{3} f^{2} - 8 \, c d^{2} e^{2} f g + 3 \, {\left (c d^{3} e + a d e^{3}\right )} g^{2}\right )} x\right )} \sqrt {-e^{2} f + d e g} \arctan \left (\frac {\sqrt {-e^{2} f + d e g} \sqrt {g x + f}}{e g x + e f}\right ) + {\left (2 \, {\left (3 \, c d^{2} e^{3} - a e^{5}\right )} f^{2} - {\left (9 \, c d^{3} e^{2} - 7 \, a d e^{4}\right )} f g + {\left (3 \, c d^{4} e - 5 \, a d^{2} e^{3}\right )} g^{2} + {\left (8 \, c d e^{4} f^{2} - {\left (13 \, c d^{2} e^{3} - 3 \, a e^{5}\right )} f g + {\left (5 \, c d^{3} e^{2} - 3 \, a d e^{4}\right )} g^{2}\right )} x\right )} \sqrt {g x + f}}{4 \, {\left (d^{2} e^{6} f^{3} - 3 \, d^{3} e^{5} f^{2} g + 3 \, d^{4} e^{4} f g^{2} - d^{5} e^{3} g^{3} + {\left (e^{8} f^{3} - 3 \, d e^{7} f^{2} g + 3 \, d^{2} e^{6} f g^{2} - d^{3} e^{5} g^{3}\right )} x^{2} + 2 \, {\left (d e^{7} f^{3} - 3 \, d^{2} e^{6} f^{2} g + 3 \, d^{3} e^{5} f g^{2} - d^{4} e^{4} g^{3}\right )} x\right )}}\right ] \]
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Timed out. \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.28 (sec) , antiderivative size = 285, normalized size of antiderivative = 1.60 \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=\frac {{\left (8 \, c e^{2} f^{2} - 8 \, c d e f g + 3 \, c d^{2} g^{2} + 3 \, a e^{2} g^{2}\right )} \arctan \left (\frac {\sqrt {g x + f} e}{\sqrt {-e^{2} f + d e g}}\right )}{4 \, {\left (e^{4} f^{2} - 2 \, d e^{3} f g + d^{2} e^{2} g^{2}\right )} \sqrt {-e^{2} f + d e g}} + \frac {8 \, {\left (g x + f\right )}^{\frac {3}{2}} c d e^{2} f g - 8 \, \sqrt {g x + f} c d e^{2} f^{2} g - 5 \, {\left (g x + f\right )}^{\frac {3}{2}} c d^{2} e g^{2} + 3 \, {\left (g x + f\right )}^{\frac {3}{2}} a e^{3} g^{2} + 11 \, \sqrt {g x + f} c d^{2} e f g^{2} - 5 \, \sqrt {g x + f} a e^{3} f g^{2} - 3 \, \sqrt {g x + f} c d^{3} g^{3} + 5 \, \sqrt {g x + f} a d e^{2} g^{3}}{4 \, {\left (e^{4} f^{2} - 2 \, d e^{3} f g + d^{2} e^{2} g^{2}\right )} {\left ({\left (g x + f\right )} e - e f + d g\right )}^{2}} \]
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Time = 12.01 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.26 \[ \int \frac {a+c x^2}{(d+e x)^3 \sqrt {f+g x}} \, dx=\frac {\frac {\sqrt {f+g\,x}\,\left (-3\,c\,d^2\,g^2+8\,c\,f\,d\,e\,g+5\,a\,e^2\,g^2\right )}{4\,e^2\,\left (d\,g-e\,f\right )}+\frac {{\left (f+g\,x\right )}^{3/2}\,\left (-5\,c\,d^2\,g^2+8\,c\,f\,d\,e\,g+3\,a\,e^2\,g^2\right )}{4\,e\,{\left (d\,g-e\,f\right )}^2}}{e^2\,{\left (f+g\,x\right )}^2-\left (f+g\,x\right )\,\left (2\,e^2\,f-2\,d\,e\,g\right )+d^2\,g^2+e^2\,f^2-2\,d\,e\,f\,g}+\frac {\mathrm {atan}\left (\frac {\sqrt {e}\,\sqrt {f+g\,x}}{\sqrt {d\,g-e\,f}}\right )\,\left (3\,c\,d^2\,g^2-8\,c\,d\,e\,f\,g+8\,c\,e^2\,f^2+3\,a\,e^2\,g^2\right )}{4\,e^{5/2}\,{\left (d\,g-e\,f\right )}^{5/2}} \]
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